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Q.

A 0.001 molal solution of [Pt(NH3)4Cl4] in water had a freezing point depression of 0.0054oC. If Kf for water is 1.80, the correct formulation for the above molecule is 

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a

[Pt(NH3)4Cl4]

b

[Pt(NH3)4Cl3]Cl

c

[Pt(NH3)4Cl2]Cl2

d

[Pt(NH3)4Cl2]Cl3

answer is B.

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Detailed Solution

ΔTf=imkf;0.0054=i×1.8×0.001i=3So it is PtNH34ClCl2

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