A 0.0020 m aqueous solution in an ionic compound Co(NH₃)₅(NO₂)Cl freezes at –0.00732⁰C. Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be (K_f = +1.86^oC/m)

Complete Solution:

To find the number of moles of ions produced, use the formula:

ΔT_f = i × K_f × m

Given ΔT_f = 0.00732°C, K_f = 1.86°C/m, and m = 0.0020:

i = ΔT_f / (K_f × m) = 0.00732 / (1.86 × 0.0020) = 1.97 ≈ 2

Final Answer

Therefore, 1 mole of Co(NH₃)₅(NO₂)Cl produces approximately 2 moles of ions.