A 0.0020 m aqueous solution of an ionic compound CoNH35NO2Cl freezes at −0.00732∘C Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be Kf=−1.86∘C/m

ΔTf=0−−0.00732∘=0.00732 ΔTf=i×Kf×m i=ΔTfKf×m=0.007321.86×0.002=2

A 0.0020 m aqueous solution of an ionic compound CoNH35NO2Cl freezes at −0.00732∘C Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be Kf=−1.86∘C/m

ΔTf=0−−0.00732∘=0.00732 ΔTf=i×Kf×m i=ΔTfKf×m=0.007321.86×0.002=2

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A 0.0020 m aqueous solution of an ionic compound $Co {({NH}_{3})}_{5} ({NO}_{2}) Cl freezes at - 0 {.00732}^{\circ} C$ Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be $(K_{f} = - 1 {.86}^{\circ} C / m)$

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${ΔT}_{f} = 0 - (- 0 {.00732}^{\circ}) = 0 .00732 {ΔT}_{f} = i \times K_{f} \times m i = \frac{{ΔT}_{f}}{K_{f} \times m} = \frac{0 .00732}{1 .86 \times 0 .002} = 2$

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A 0.0020 m aqueous solution of an ionic compound CoNH35NO2Cl freezes at −0.00732∘C Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be Kf=−1.86∘C/m

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A 0.0020 m aqueous solution of an ionic compound $Co {({NH}_{3})}_{5} ({NO}_{2}) Cl freezes at - 0 {.00732}^{\circ} C$ Number of moles of ions which 1 mol of ionic compound produces on being dissolved in water will be $(K_{f} = - 1 {.86}^{\circ} C / m)$