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A 0.1 molal solution of NaCl found to be isotonic with 1% urea solution. Calculate α and i for NaCl

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i = 3.66, α = 2.66

i = 1.66 , α = 2.66

i = 2.66 , α = 0.66

i = 1.66 ,α = 0.66

answer is A.

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Detailed Solution

$i_{1} {(CM)}_{1} = i_{2} {(CM)}_{2} i_{1} (0.1) = 1 x \frac{(\frac{W}{V}) % x 10}{M . W} \Rightarrow i_{1} = \frac{1 x 10}{60 x 0.1} \Rightarrow i = \frac{10}{6} = 1.66 α = \frac{i - 1}{n - 1} α = \frac{1 .66 - 1}{2 - 1} = 0 .66$

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