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A 0.50 gm ball carries a charge of magnitude 10 $μ$ C . It is suspended by a string in a downward electric field of intensity 300 N/C. If the charge on the ball is positive, then the tension in the string is: (g = 10 ms^–2)

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5 × 10^–3 N

8 × 10^–3 N

2 × 10^–3 N

zero

answer is B.

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Detailed Solution

$\begin{array}{l} T = mg + Eq \\ = (0 .5 \times 10^{- 3} \times 10) + (300 \times 10 \times 10^{- 6}) \\ = 5 \times 10^{- 3} + 3 \times 10^{- 3} = 8 \times 10^{- 3} N \end{array}$

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