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A 0.50 gm ball carries a charge of magnitude 10 $μC$ . It is suspended by a string in a downward electric field of intensity 300N/C. If the charge on the ball is positive, then the tension in the string is (g=10ms^-2)

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$6 \times 10^{- 3} N$

$8 \times 10^{- 2} N$

$8 \times 10^{- 3} N$

$6 \times 10^{- 2} N$

answer is B.

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Detailed Solution

$T = mg + Eq = 5 \times 10^{- 4} \times 10 + 300 \times 10 \times 10^{- 6} = 8 \times 10^{- 3} N$

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