A 1 M solution of glucose reaches dissociation equilibrium according to equation given below 6HCHO ⇌ C6H12O6. What is the concentration of HCHO at equilibrium if equilibrium constant is 6 × 1022

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A 1 M solution of glucose reaches dissociation equilibrium according to equation given below $6 HCHO ⇌ C_{6} H_{12} O_{6} .$ What is the concentration of HCHO at equilibrium if equilibrium constant is $6 \times 10^{22}$

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$3.2 \times 10^{- 4} M$

$1.6 \times 10^{- 8} M$

$1.6 \times 10^{- 4} M$

$3.2 \times 10^{- 6} M$

answer is D.

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Detailed Solution

$6 HCHO ⇌ C_{6} H_{12} O_{6}$ forward reaction

$C_{6} H_{12} O_{6} ⇌ 6 HCHO$ backward reaction

$K_{2} = {[\frac{1}{K_{1}}]}^{1 / 6}; K_{2} = {[\frac{1}{6 \times 10^{22}}]}^{1 / 6}$

$K_{2} = 1.6 \times 10^{- 4} M$

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