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Q.

A 10 μC charge is divided into two parts and placed at 1 cm distance so that the repulsive force between them is maximum. The charges of the two parts are:

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a

9 μC, 1 μC

b

5 μC, 5 μC

c

8 μC, 2 μC

d

7 μC, 3 μC

answer is A.

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Detailed Solution

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F=k(q)(Q−q)r2 

F will be maximum if dFdq=0 

Q−2q=0⇒q=Q2

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