A 10 eV electron is circulating in a plane at right angles to a uniform field of magnetic induction 10^-4 Wb/m² (= 1.0 gauss), the orbital radius of electron is

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12 cm

11cm

18 cm

16 cm

answer is C.

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Detailed Solution

K.E. of electrons $= 10 eV$
$∴ \frac{1}{2} {mv}^{2} = 10 \times (1 .6 \times 10^{- 19})$
or $V = 1 \cdot 875 \times 10^{6} m / s and Bev = \frac{{mv}^{2}}{r}$
or $r = \frac{mv}{eB} = 11 \times 10^{- 2} m = 11 cm$

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