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Q.

A 10 g mixture of hydrogen and helium is contained in a vessel of capacity 0.0125 m³ at 6 bar and 27°C. The mass of helium in the mixture is _______ g. (nearest integer)
Given : R = 8.3 JK^–1mol^–1 (Atomic masses of H and He are 1u and 4u, respectively)

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answer is 8.

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Detailed Solution

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$\begin{array}{l} PV = n_{mix} RT \\ n_{mix} = \frac{6 \times 12 .5}{0 .083 \times 300} \approx 3 \end{array}$

Let mole of He = x

Mole of H₂ = 3 – x

4x + 2(3 – x) = 10

x = 2 mol

Mass of He = 8g

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A 10 g mixture of hydrogen and helium is contained in a vessel of capacity 0.0125 m3 at 6 bar and 27°C. The mass of helium in the mixture is _______ g. (nearest integer)Given : R = 8.3 JK–1mol–1 (Atomic masses of H and He are 1u and 4u, respectively)