A 10 H.P. motor pumps out water from a well of depth 20m and fills a water tank of volume 22380 litres at a height of 10m from the ground. the running time of the motor to fill the empty water tank is $(g = 10 {ms}^{- 2})$

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answer is C.

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Detailed Solution

Volume of water to raise = 22380 l = $22380 \times 10^{- 3} m^{3}$

$P = \frac{mgh}{t} = \frac{Vρgh}{t} \Rightarrow t = \frac{Vρgh}{P}$

$t = \frac{22380 \times 10^{- 3} \times 10^{3} \times 10 \times 10}{10 \times 746} = 15 \min$

t= 300 sec =15 min

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