Q.

A 1.0 M solution of Cd+2 is added to excess iron and the system is allowed to reach equilibrium. What is the concentration of Cd+2?Cd2+(aq)+Fe(s)Cd(s)+Fe2+(aq);E0=0.037

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a

0.097

b

0.145

c

0.195

d

0.053

answer is C.

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Detailed Solution

Cd+2+FeFe+2+CdE=E0(0.0591/n)logQ0=0.037(0.0591/2)logFe+2/Cd+2logFe+2/Cd+2=0.037×2/0.0591=1.25Fe+2=0.95;Cd+2=0.053

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