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A $100 μ F$ capacitor in series with a $40 Ω$ resistance is connected to AC of 110 V, 60 Hz supply. Then time lag between the current maximum and the voltage maximum is [tan 33.5 = 0.66]

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1.55 ms

15.5 ms

1.55 s

15.5 s

answer is A.

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Detailed Solution

$ω = 2 πf = 120 π$

$tanϕ = \frac{1 / ωC}{R} = 0.6635$

$ϕ = 33.56 π / 180 r a d$

Time lag is $\frac{ϕ}{ω} = 1.55 ms$

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