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Q.

A 100 g iron ball having velocity 10 m/s collides with a wall at an angle 30° and rebounds with the same angle. If the period of contact between the ball and wall is 0.1 second, then the force experienced by the wall is

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a

0.1 N

b

10 N

c

100 N

d

1.0 N

answer is A.

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Detailed Solution

During collision of ball with the wall horizontal momentum changes (vertical momentum remains constant)
$∴ F = \frac{Change in horizontal momentum}{Time of contact}$
$= \frac{2 Pcos 60^{o}}{0 .1} = \frac{2 mvcos 60^{o}}{0 .1}$
$= \frac{2 \times 0 .1 \times 10 \times 1}{0 .1 \times 2} = 10 N$

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