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A 100 meter halo-tube of uniform thickness has two open ends X and Y. Ammonia gas is sent into the tube from end X and hydrogen chloride from end Y. Simultaneously. At what distance from end ‘X’, the gases first meet to form a smoke ring?

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59.7m

59.5m

59.8m

59.9m

answer is B.

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Detailed Solution

$\frac{r_{1}}{r_{2}} = \sqrt{\frac{M_{2}}{M_{1}}} = \sqrt{\frac{36.5}{17}} = 1.47$

$\frac{1.47}{1} = \frac{l}{100 - l}$

$l = 59.5 M$

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