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Q.

A 100 turn closely wound circular coil of radius 10 cm carries a current of 3.2 A.
a. What is the field at the centre of the coil?
b. What is the magnetic moment of this coil?

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Detailed Solution

a. Magnetic filed at the centre of the coil,
B=μ0ni2r=4π×10−7×100×3.22×10×10−2=2×10−3T
b. The magnetic moment is given by,
M=niA=niπr2=100×3.2×3.14×10−2=10Am2

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