A 100 watt bulb emits monochromatic light of wavelength 400nm. Calculate the number of photons emitted per second by the bulb

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A 100 watt bulb emits monochromatic light of wavelength 400nm. Calculate the number of photons emitted per second by the bulb

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$2.012 \times 10^{20}$

$2.012 \times 10^{21}$

$2.012 \times 10^{24}$

$2.012 \times 10^{19}$

answer is B.

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Detailed Solution

Power of the bulb = 100 watt = 100 T/sec

Energy of photo $E = h ϑ$

$E = \frac{h c}{λ}$

$= \frac{6.626 \times 10^{- 34} 1.5 \times 3 \times 10^{8} n / \sec}{400 \times 10^{- 9} n m} = 4.969 \times 10^{- 19} J$

Number of photon emitted = $\frac{100 J / \sec}{4.969 \times 10^{- 19} J} = 2.012 \times 10^{20} \sec$

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