A 100 watt bulb working on 200 volt and a 200 watt bulb working on 100 volt have:

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Resistances in the ratio of 4:1

Maximum current ratings in the ratio of 1:4

Maximum current ratings in the ratio of 1:2

Resistances in the ratio of 2 : 1

answer is B.

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Detailed Solution

$R = \frac{V^{2}}{P} \Rightarrow R_{1} = \frac{200 \times 200}{100} = 400 Ω$ $and R_{2} = \frac{100 \times 100}{200} = 50 Ω$

Maximum current rating $i = \frac{P}{V}$

$So i_{1} = \frac{100}{200} and i_{2} = \frac{200}{100} \Rightarrow \frac{i_{1}}{i_{2}} = \frac{1}{4}$

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