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Q.

A=1000110-24;I=100010001 and A-1=16(A2+CA+DI). The values of C and D are

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a

(–6, –11)

b

(6, 11)

c

(–6, 11)

d

(6, –11)

answer is C.

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Detailed Solution

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A=1000110-24trace(A)=1+1+4=6

Sum of Minor of Principle diagonal

=11-24+1004+1001 =4+2+4+1=11 |A|=1 (4+2)=6 A3-6A2+11A-6I=0 A-1 A3-6A2+11A-6I=0 A-1 A A2-6A-1 A A+11A-1 A-6A-1 I=0 I A2-6IA+11I-6A-1=0 6A-1=A2-6A+11I A-1=16 A2-6A+11 I C=-6,  D=11 (C, D)=(-6, 11)

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