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Q.

A 100ml aqueous solution containing 0.1M $C H_{3} C O O N a$ functions as anode during electrolysis. If $H_{2} O_{(l)}$ is oxidized at anode during electrolysis calculate pH of solution after passing 10/3 milli Faraday of charge. Round off your answer to nearest integer.
$P^{k a} C H_{3} C O O H = 4.7 (\log 2 = 0.3, \log 3 = 0.48)$

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answer is 5.

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Detailed Solution

$H_{2} O \to \frac{1}{2} O_{2} + 2 H^{\oplus} + 2_{- 1} ° e$

$C H_{3} C O O^{-} + H^{\oplus} \to C H_{3} C O O H$

10 10/3 10/3 20/3

$p H = 4.7 + \log 2 = 5.0$

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