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A 100W bulb is connected to an AC source of 220V, 50Hz. Then the current following through the bulb is

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$\frac{5}{11} A$

$\frac{1}{2} A$

$\frac{3}{4} A$

answer is A.

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Detailed Solution

P=100 W frequency of ac source

$\begin{array}{l} I_{r m s} = \frac{P}{V_{r m s}} = \frac{100}{200} \\ V_{r m s} = 220 H z, v = 50 H z = \frac{5}{11} A \end{array}$

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