A 1.0g sample of pyrolusite ore containing MnO₂ (MW = 87) was dissolved in a concentrated HCl solution and liberated Cl₂(g) was passed through a concentrated KI solution releasing I₂. If the liberated iodine required 16mL of 1.25 M sodium thiosulphate (Na₂S₂O₃) solution, mass percentage of MnO₂ in the given sample is

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87%

43.5%

0.875%

21.75 %

answer is B.

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Detailed Solution

No.of m.eqts. MnO₂ = No.of m.eqts. of Cl₂
= No.of m.eqts. of KI = No.of m.eqts. hypo
No.of m.eqts of MnO2
$= 16 \times 1 .25 = 16 \times \frac{5}{4} = 20$
No.of milli moles of MnO₂ = 10
Weight of MnO₂ = $10 \times 87 \times 10^{- 3} = 0 .87 g$
Weight % of ${MnO}_{2} = \frac{0 .87}{1} \times 100 = 87 %$

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