A 10kg mass moves along x-axis. Its acceleration as a function of its position is shown in the figure. What is the total work done on the mass by the force as the mass moves from $\mathrm{x}=0$ to $\mathrm{x}=8\mathrm{cm}$

Work done = Area covered in between force displacement curve and displacement axis

= Mass $\times$ Area covered in between acceleration-displacement curve and displacement axis.
$=10\times \frac{1}{2}(8\times {10}^{-2}\times 20\times {10}^{-2})$

$=8\times {10}^{-2}\mathrm{J}$