A 10L flask contains 41.4g of a mixture of gases $C_{x} H_{8}$ and $C_{x} H_{12}$ . The total pressure of $44^{0} C$ in the flask is 1.56 atm. Analysis revealed that the gas mixture has 87% total carbon and 13% total H. The value of ‘X’.

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answer is 5.

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Detailed Solution

From PV=nRT, total moles =0.6.

Let $C_{x} H_{8}$ be ‘a’ mole therefore moles of $C_{x} H_{12} = (0.6 - a)$ mole

Mass of ‘c’ in ‘a’ mole of $C_{x} H_{8} = 12 a x g$ .

Mass of ‘c’ in $|0.6 - a|$ mole of $C_{x} H_{12} = 12 (0.6 - a) g$ .

Therefore total mass of c in mixture = 41.4g and x=5.

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