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A 110 V, 50 Hz, AC source is connected in the circuit (as shown in figure). The current through the resistance $55 Ω$ ,at resonance in the circuit, will be_________A.

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Detailed Solution

At resonance $I_{L} = I_{C}$

Alternatively, $\frac{1}{Z} = \sqrt{{(\frac{1}{X_{L}} - \frac{1}{X_{C}})}^{2}}$

At resoancne, $X_{L} = X_{C}$ and $Z \to \infty$

$∴ Z_{t o t a l c i r c u i t} \to \infty i . e, I = 0$

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