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Q.

A 12 ohm resistor and a 0.21 henry inductor are connected in series to an ac source operating at 20 volts, 50 cycle/second. The phase angle between the current and the source voltage is (tan-15.5 = 800 approx)

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a

40°

b

90°

c

30°

d

80°

answer is C.

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Detailed Solution

tanφ=ωLR=2π×50×0.2112=5.5 ⇒ φ=80o

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