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A 12 V, 24 W tungsten filament bulb is supplied the current from n cells connected in series. Each cell has an emf 1.5 V and internal resistance of 0.25 Ω. What is the value of n in order that the bulb runs at its rated power?

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answer is C.

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Detailed Solution

W= VI. Therefore I= W/V= 24/12 = 2A. Resistance of the bulb is R = 12/2 = 6 Ω . If n cells are used, then

$i = \frac{n E}{R + n R}$

$\frac{n X 1.5}{6 + n \times 0.25} = 2$

which gives n = 12.

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