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Q.

A 12 V battery connected to a resistance $6 Ω$ through a switch, drives a constant current in the circuit. The switch is opened in 1ms. The emf induced across the coil is 20 V. The inductance of the coil is :

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a

8 mH

b

10 mH

c

5 mH

d

12 mH

answer is B.

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Detailed Solution

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$I_{i} = \frac{V_{0}}{R} = \frac{12 V}{6 Ω} = 2 A$

$ε = - L \frac{ΔI}{Δt} = - (\frac{0 - 2}{10^{- 3}}) L = 20$

$\Rightarrow L = 10 mH$

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