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A 1250 W heater operates at 115 V. What is the resistance of the heating coil?

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1.6 $Ω$

13.5 $Ω$

1250 $Ω$

10.6 $Ω$

answer is D.

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Detailed Solution

Given, V = 115 V
and P = 1250 W

We know $R = \frac{V^{2}}{P}$

So, $R = \frac{(115)^{2}}{1250} = 10.58 Ω$

Resistance, R = 10.6 $Ω$

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