A 1kg ball moving at 12 ms^-1 collides head on with a 2kg ball moving in the opposite direction at 24 m/s. The velocity of each ball after the impact, if the coefficient of restitution is 2/3, is

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-20 m/s; -4 m/s

20 m/s; 24 m/s

-28 m/s; -4 m/s

28 m/s; –4 m/s

answer is A.

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Detailed Solution

$v_{1} = (\frac{m_{1} - {em}_{2}}{m_{1} + m_{2}}) u_{1} + \frac{(1 + e) m_{2} u_{2}}{m_{1} + m_{2}} = - 28 m / s$

$v_{2} = \frac{(1 + e) m_{1} u_{1}}{m_{1} + m_{2}} + (\frac{m_{2} - {em}_{1}}{m_{1} + m_{2}}) u_{2} = - 4 m / s$

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