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Q.

A 2 kg block is pushed against a vertical wall by applying a horizontal force of 50 N. The coefficient of static friction between the block and the wall is 0.5. A force F is also applied on the block vertically upward(as shown in figure). The maximum value of F applied, so that the block does not move upward, will be (g=10 ms^-2)

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a

20 N

b

25 N

c

10 N

d

45 N

answer is D.

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Detailed Solution

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$F = 2 \times 10 + 0.5 \times 50 = 20 + 25 = 45 N F maximum that can be applied is 45 N$

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A 2 kg block is pushed against a vertical wall by applying a horizontal force of 50 N. The coefficient of static friction between the block and the wall is 0.5. A force F is also applied on the block vertically upward(as shown in figure). The maximum value of F applied, so that the block does not move upward, will be (g=10 ms-2)