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Q.

A 2 kg copper block is heated to $500 º C$ and then it is placed on a large block of ice at $0 º C$ . If the specific heat capacity of copper is $400 J / k g º C$ and latent heat of fusion of water is $3.5 \times 10^{5} J / k g$ , the amount of ice that can melt is :

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a

$\frac{7}{3} k g$

b

$\frac{7}{5} k g$

c

$\frac{7}{8} k g$

d

$\frac{8}{7} k g$

answer is B.

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Detailed Solution

$m . s . Δ θ = m^{1} L$
$2 \times 400 \times 500 = m^{1} \times 3.5 \times 10^{5}$
$m^{1} = \frac{8}{7} k g$

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