A 20 % (wt/wt) HNO3, (d =1.115 g cm-3) is diluted with water until the acid is 11% (wt/wt) (d = 1.060 g cm-3). The molarity difference between the solutions is

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A 20 % (wt/wt) HNO₃, (d =1.115 g cm^-3) is diluted with water until the acid is 11% (wt/wt) (d = 1.060 g cm^-3). The molarity difference between the solutions is

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answer is A.

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Detailed Solution

$Molarity of 20 wt % acid = \frac{1000 \times 20 \times 1 .115}{63 \times 100} = 3 .54 M$
$Molarity of 11 % wt % acid = \frac{1000 \times 11 \times 1 .06}{63 \times 100} = 1 .85 M$
$∴ Δ (molarity) = 3 .54 - 1 .85 = 1 .69 M .$