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Q.

A 2.0 cm high object is placed perpendicular to the principal axis of a concave mirror. The distance of the object from the mirror is 30 cm, and its image is formed 60 cm from the mirror, on the same side of the mirror as the object. Find the height of the image formed.

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a

2 cm

b

4 cm

c

8 cm

d

6 cm

answer is B.

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Detailed Solution

We have, u = – 30 cm and v = – 60 cm

$Thus m = \frac{h_{e}}{h_{0}} = - \frac{v}{u} = - \frac{- 60 cm}{- 30 cm} = - 2 or h_{e} = - 2 h_{0} = - 2 \times 2.0 cm = - 4.0 cm$

The height of the image is 4.0 cm.

The minus sign shows that it is on the other side of the axis, i.e., it is inverted.

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A 2.0 cm high object is placed perpendicular to the principal axis of a concave mirror. The distance of the object from the mirror is 30 cm, and its image is formed 60 cm from the mirror, on the same side of the mirror as the object. Find the height of the image formed.