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A 20 cm tall object is placed 20 cm from a concave mirror of focal length 10 cm. What is the size and nature of the image

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2 cm, virtual

4 cm, virtual

2 cm, real

4 cm, real

answer is C.

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Detailed Solution

u = - 20 c m; f = - 10 c m, h_{o} = 2 c m

$\frac{1}{v} = \frac{1}{- 10} + \frac{1}{20} \Rightarrow \frac{1}{v} = \frac{- 1}{20}$

$v = - 20 c m$

Magnification $m = \frac{- v}{u} \Rightarrow m = - 1; r e a l i m a g e$

Size of the object is equal to size of image

$h_{i} = h_{o} = 2 c m$

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