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Q.

A 2.0 g sample containing MnO2 is treated with HCl liberating Cl2. The Cl2 gas is passed into a solution of KI and 60.0 mL of 0.1MNa2S2O3 is required to titrate the liberated iodine. The percentage of MnO2 in the sample is______. (Nearest integer)

[Atomic masses (in u) Mn=55; Cl=35.5; O=16; I=127; Na=23; K=39; S=32] 

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answer is 13.05.

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Detailed Solution

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MnO26 meq=3 m mol+HClCl2+Mn2+6 meq Cl26 meq+KICl-+I2          6 meq
I26 meq+Na2S2O36 m mol=6 meqI+Na2S4O6
%MnO2=3×103×872×100             =13.05%

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