A $20 k g$ block is initially at rest on a horizontal surface for which the coefficient of friction is $0.6$ . If a horizontal force F is applied such that it varies with time as shown in figure. Determine the speed of the block (in m/s) after $10 s$ . $(g = 10 m / s^{2})$

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answer is 24.

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Detailed Solution

frmax $= 0.6 m g = 120 N$
In the figure acting friction force shown by OAB
Net change in momentum of body = Area of ACDB
$m v = \frac{1}{2} (7 + 5) \times 80$
$v = 24 m / s$

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