Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6

Q.

A 20 litre container at 400 K contains CO2(g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the container is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when pressure of CO2 attains its maximum value, will be 
 (GiventhatSrCO3(s)SrO(s)+CO2(g),Kp=1.6atm

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away
An Intiative by Sri Chaitanya

a

10 litre

b

4 litre

c

2 litre

d

5 litre

answer is D.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

SrCO3(s)SrO(s)+CO2(g);Kp=1.6 atm Kp=PCO2×pSrOpSrCO3 1.6=pCO2                     pSrO=pSrCO3=1

  Maximum pressure of CO2=1.6 atm

Let the maximum volume of the container when pressure of CO2 is 1.6 atm  be V  Lit During the process, PV = constant

 0.4×20=1.6×VV=0.4×201.6=5 L

Watch 3-min video & get full concept clarity

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon