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A 20 litre container at 400K contains CO₂(g) at pressure 0.4atm and an excess of SrO (neglect the volume of solid SrO). The volume of the container is now decreased by moving the movable piston fitted in the container. The maximum volume of the container, when pressure of CO₂ attiains its maximum value, will be
$[Given that : {SrCO}_{3} (s) ⇌ SrO (s) + {CO}_{2} (g), Kp = 1 .6 atm ]$

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4 litre

10 litre

5 litre

2 litre

answer is D.

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Detailed Solution

${SrCO}_{3} (s) ⇌ SrO (s) + {CO}_{2} (g)$
$K_{p} = P_{{CO}_{2}}$
maximum pressure of ${CO}_{2} = 1 .6 atm$
$\begin{array}{l} P_{1} V_{1} = P_{2} V_{2} \\ 0 .4 \times 20 = 1 .6 V_{2} \Rightarrow V_{2} = 5 L \end{array}$

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