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Q.

A 200 ml mixture of CO and CO2 is passed through excess of red hot charcoal causing the following reaction
CO2(g)+C(S)2CO(g)
After passing the gas through charcoal, volume increased to 270ml . Select the correct statements.

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a

If original mixture was passed through KOH solution volume would have reduced to 70ml

b

Volume percentage of CO in the original mixture is 65%

c

Mole fraction of CO2 in the original mixture will be 0.35

d

Minimum moles of red hot charcoal required for complete conversion of CO2 should be 100 milli moles

answer is B, C.

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Detailed Solution

CO2+C2CO
 The volume of CO2 in the original mixture is 70 ml
Volume percentage is 65%
Mole fraction of CO2 0.35

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