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Q.

A 200 ml mixture of CO and CO2 is passed through excess of red hot charcoal causing the following reaction

CO2(g)+C(s)2CO(g)

After passing the gas through charcoal, volume increased to 270 ml. Select the correct statement(s)

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a

Volume percentage of CO in the original mixture is 65%

 

b

If original mixture was passed through KOH solution volume would have reduced to  70 ml

c

Mole fraction of  CO2 in the original mixture will be 0.35

d

Minimum moles of red hot chareoal required for complete conversion of  CO2 should be 70 millimoles

answer is A, C.

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Detailed Solution

CO2+C2COV  (200V)  (200V+2V)=270 V=70ml

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