Q.

A 20g  piece of iron  specific heat capacity =0.5J/g0c at 200°C is immersed in 100g of water at 27°C what will be the temperature (°C) of this system at thermal equilibrium?

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answer is 31.

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Detailed Solution

At equilibrium
Heat lost by iron =heat gain by water
20×0.5×(473T)=100×4.2(T300)T=304K=310C

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A 20g  piece of iron  specific heat capacity =0.5J/g0c at 200°C is immersed in 100g of water at 27°C what will be the temperature (°C) of this system at thermal equilibrium?