A 20g piece of iron $[specific heat capacity = 0.5 J / g^{0} c]$ at 200°C is immersed in 100g of water at 27°C what will be the temperature (°C) of this system at thermal equilibrium?

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answer is 31.

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Detailed Solution

At equilibrium
Heat lost by iron =heat gain by water
$\begin{array}{l} 20 \times 0.5 \times (473 - T) = 100 \times 4.2 (T - 300) \\ T = 304 K = 31^{0} C \end{array}$

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