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Q.

A 20g piece of iron (specific heat capacity =0.5 J/gC ) at 200C is immersed in 100g water of 27C . What will be the temperature  C) of this system of thermal equilibrium

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answer is 31.

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Detailed Solution

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At equilibrium Heat lost by iron = Heat gain by water

20×0.5×(473-T)  =100×4.2×(T-300)  T =304K=31C

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