A 2100 W continuous flow geyser (instant geyser) has water inlet temperature $= 10 ° C$ while the water flows out at the rate of 20 g/sec. The outlet temperature of water must be about

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$20 ° C$

$30 ° C$

$35 ° C$

$40 ° C$

answer is C.

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Detailed Solution

$i . e . \frac{d Q}{d t} = \frac{d m}{d t} = \frac{d m}{d t} s Δ T$

On putting the values, we get
$2100 = 0.02 \times 4200 Δ T$

Or $Δ T = \frac{2100}{0.02 \times 4200} = 25$

As $Δ T = T_{f} - T_{i}$

Hence $T_{f} - 10 = 25$
Or $T_{f} = 35^{0}$

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