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A 21.2 kg object oscillates at the end of a vertical spring that has a spring constant of 20500N/m. The effect of air resistance is represented by damping coefficient, b = 2Ns/m. The time interval that elapses while the energy of the system drops to 10% of its initial value is (Given $l n (10)$ =2.3)

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An Intiative by Sri Chaitanya

34.4

12.2

24.4 s

839 s

answer is C.

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Detailed Solution

A = A 0 e − b t / 2 m; E α A 2

; Hence

E = E 0 e − b t / m ⇒ E 0 10 = E 0 e − b t / m ⇒ t = m ln 10 b = 24.4

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