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A 2.24litre cylinder containing O₂ gas at 27°C and 2 atm is found to develop a leakage. When the leakage was repaired, the pressure dropped to 100 cm of Hg at 27°C. The number of mole of gas escaped out during leakage is:

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0.06

0.05

0.07

0.08

answer is A.

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Detailed Solution

PV = nRT
Initially : $2 \times 2.24 = n_{1} \times \frac{22.4}{273} \times 300 n_{1} = 0.182$

$Finally : \frac{100}{76} \times 2 .24 = n_{1} \times \frac{22.4}{273} \times 300 n_{2} =0.120 {no.of moles escaped=n}_{1} {-n}_{2} =0.18-0.12=0.06 moles$ ;

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