A 240 V, 200 W bulb is connected to a 210 V source. Determine the bulb's power consumption.

Electrical power is the rate at which electrical energy is converted into other kinds of energy.

$$\begin{gathered} P=\frac{W}{t} \\ =VI \\ =I^{2}R \\ =\frac{V^2}{R} \end{gathered}$$

Where V=  Potential difference, R=  Resistance, and I= current.

Given - Potential difference V= 240V, the power of the bulb P= 200W  and the actual voltage $\left(V^{\text{'}}\right)=210 \mathrm{V}$.

The calculation for the bulb's resistance is as follows:

$$\begin{gathered} \Rightarrow R=\frac{V^2}{P} \\ =\frac{(240{)}^2}{200} \\ =288\Omega \end{gathered}$$

The bulb's power consumption is as follows:

$$\begin{gathered} \Rightarrow P=\frac{V^2}{R} \\ =\frac{(210{)}^2}{288} \\ =153 \mathrm{W} \end{gathered}$$