A 250-turn rectangular coil of length 2.1 cm and width 1.25 cm carries a current of 85µA and subjected to a magnetic field of strength 0.85 T. Work done for rotating the coil by 180⁰ against the torque is:

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9.1µJ

2.3µJ

4.55µJ

1.15µJ

answer is B.

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Detailed Solution

$W = MB (1 - \cos θ) = MB (1 - (- 1)) = 2 MB = 2 (NiA) B = 2 \times 250 \times 85 \times 10^{- 6} \times 2 .1 \times 1 .25 \times 10^{- 4} \times 0 .85 = 9 .4 μJ$

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