A 27 % (wt/wt) aqueous ammonia has a specific gravity of 0.90 at 298 K. Correct statements are

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The molality of the solution of NH₄OH is 10.57

The normality of NH₄OH solution is 7.5

The mole fraction of water in the solution is 0.78

10 mL of the above solution is diluted to a litre. 10 mL of the diluted solution requires 12.5 mL of 0.05 NHCI for complete neutralisation. The strength of this ammonia solution is 0.063 N.

answer is A, C, D.

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Detailed Solution

(a) Weight of water in 100 gm solution
= 100-27= 73gm
Molality of NH₄OH $= \frac{1000 \times 27}{35 \times 73} = 10 .57$
(b) 100 gms of solution $= \frac{100}{0 .90} = 111 .1 {cm}^{3}$
Normality- of solution $= \frac{1000 \times 27}{35 \times 111 .1} = 6 .9$
(c) Moles of NH₃ $= \frac{27}{17}, moles of H_{2} O = \frac{100}{18}$
$X_{water} = \frac{100 / 18}{\frac{100}{18} + \frac{27}{17}} = \frac{5 .55}{5 .55 + 1 .59} = 0 .78$
(d) Strength of diluted ammonia solution $= \frac{12.5 \times 0.05}{10} = 0.063 N$