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A 280 days old radioactive substance shows an activity of 6000 dps, 140 days later it’s activity becomes 3000 dps. Its initial activity is K $×1 0^{3} dps$ then K is

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Detailed Solution

$A_{1} = λ N_{1} = λ N_{0} e^{- λ t_{1}}, A_{2} = λ N_{2} = λ N_{0} e^{- λ t_{2}}$

$A_{0} = λ N_{0} = 24000 d p s .$

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